What is the phenotype ratio for offspring produced from two heterozygous parents in a monohybrid cross?

In a monohybrid cross involving two heterozygous parents, the phenotype ratio of the offspring can be predicted using a Punnett square. Each parent contributes one allele to the offspring, and since both are heterozygous, they each have one dominant and one recessive allele.

When you set up the Punnett square for two heterozygous parents, the possible allele combinations in the offspring include:

1. The combination of two dominant alleles.

2. The combination of one dominant and one recessive allele.

3. The combination of one recessive and one dominant allele.

4. The combination of two recessive alleles.

This results in the following genotypic ratios:

• 1 homozygous dominant (AA)

• 2 heterozygous (Aa)

• 1 homozygous recessive (aa)

In terms of phenotypes, the dominant phenotype will be expressed by both the homozygous dominant and the heterozygous individuals, leading to a total of three individuals showing the dominant trait and one individual showing the recessive trait.

Consequently, the resulting phenotype ratio for the offspring is 3:1, where three offspring display the dominant phenotype and one displays the recessive phenotype.