What is the probability of obtaining a homozygous recessive offspring from a cross of two heterozygous parents?

To determine the probability of obtaining a homozygous recessive offspring from a cross between two heterozygous parents, it's important to understand the genetic makeup of the parents and the potential offspring.

In this scenario, both parents are heterozygous, meaning their genotype can be represented as Tt, where 'T' is the dominant allele and 't' is the recessive allele. When these two parents are crossed, the possible combinations of alleles in the offspring can be organized using a Punnett square.

The possible genotypes from the cross of Tt (parent 1) and Tt (parent 2) are as follows:

• TT (homozygous dominant)

• Tt (heterozygous)

• Tt (heterozygous)

• tt (homozygous recessive)

From the results in the Punnett square, we can see that there are a total of four possible genotypes:

1. TT - 1 time

2. Tt - 2 times

3. tt - 1 time

Out of these four outcomes, only one results in a homozygous recessive offspring (tt). To find the probability, we divide the number of tt outcomes by the